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軟件設(shè)計(jì)師每日一練試題(2025/11/9)

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軟件設(shè)計(jì)師每日一練試題內(nèi)容(2025/11/9)

  • 試題1

    若每一條指令都可以分解為取指、分析和執(zhí)行三步。已知取指時(shí)間t取指=5△t,分析時(shí)間t分析=2△t,執(zhí)行時(shí)間t執(zhí)行=5△t。如果按順序方式從頭到尾執(zhí)行完500 條指令需(1)△t。如果按照[執(zhí)行]k、[分析]k+1 、[取指]k+2重疊的流水線方式執(zhí)行指令,從頭到尾執(zhí)行完500 條指令需(2)△t。
    (1)A、5590
    B、5595
    C、6000
    D、6007
    (2)A、2492
    B、2500
    C、2510
    D、2515

    查看答案

    試題參考答案:C、C

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題2

    The project workbook is not so much a separate document as it is a structure imposed on the documents that the project will be producing anyway.
    All the documents of the project need to be part of this ( ). This includes objectives ,external specifications , interface specifications , technical standards , internal specifications and administrative memoranda(備忘錄).
    Technical prose is almost immortal. If one examines the genealogy ( Ff ) of a customer manual for a piece of hardware or software , one can trace not only the ideas , but also many of the very sentences and paragraphs back to the first (請(qǐng)作答此空) proposing the product or explaining the first design. For the technical writer, the paste-pot is as mighty as the pen.
    Since this is so, and since tomorrow's product-quality manuals will grow from today’s memos, it is very important to get the structure of the documentation right. The early design of the project ( ) ensures that the documentation structure itself is crafted, not haphazard. Moreover, the establishment of a structure molds later writing into segments that fit into that structure.
    The second reason for the project workbook is control of the distribution of ( ). The problem is not to restrict information, but to ensure that relevant information gets to all the people who need it.
    The first step is to number all memoranda, so that ordered lists of titles are available and h worker can see if he has what he wants. The organization of the workbook goes well beyond this to establish a tree-structure of memoranda. The ( ) allows distribution lists to be maintained by subtree, if that is desirable.
    A.objective
    B.memoranda
    C.standard
    D.specification

    查看答案

    試題參考答案:B

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題3

    進(jìn)程P1、P2、P3、P4、P5和P6的前趨勢(shì)圖如下所示,若用PV操作控制進(jìn)程P1、P2、P3、P4、P5和P6并發(fā) 執(zhí)行的過(guò)程,則需要設(shè)置7個(gè)信號(hào)量S1、S2、S3、S 4、S5、S6和S7,且信號(hào)量S1~S7的初值都等于零。

    P 1—P6的進(jìn)程執(zhí)行圖中,a和b處應(yīng)分別填寫(xiě)(  );c 和d處應(yīng)分別填寫(xiě)(  );e和f處應(yīng)分別填寫(xiě)(  );g 和h處應(yīng)分別填寫(xiě)(  )  

    問(wèn)題1
     A.V(S1)和V(S2)
     B.P(S1)和P(S2)
     C.P(S1)和V(S2)
     D.V(S1)和P(S2)
    問(wèn)題2
     A.P(S1)P(S2)和P(S3)和P(S4)
     B.V(S1)V(S2)和V(S3)和V(S4)
     C.P(S1)P(S2)和V(S3)和V(S4)
     D.V(S1)V(S2)和P(S3)和P(S4)
    問(wèn)題3
     A.P(S5)P(S6)和P(S4)和P(S5)
     B.V(S5)V(S6)和V(S4)和V(S5)
     C.P(S5)P(S6)和V(S4)和V(S5)
     D.V(S5)V(S6)和P(S4)和P(S5)
    問(wèn)題4
     A.P(S7)和P(S6)P(S7)
     B.V(S7)和P(S6)P(S7)
     C.P(S7)和V(S6)V(S7)
     D.V(S7)和V(S6)V(S7)

    查看答案

    試題參考答案:A、C、D、B

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題4

    假設(shè)鐵路自動(dòng)售票系統(tǒng)有n個(gè)售票終端,該系統(tǒng)為每個(gè)售票終端創(chuàng)建一個(gè)進(jìn)程Pi(i=1,2,…,n)管理車(chē)票銷售過(guò)程。假設(shè)Tj(j=1,2,…,m)單元存放某日某趟車(chē)的車(chē)票剩余票數(shù),Temp為Pi進(jìn)程的臨時(shí)工作單元,x為某用戶的購(gòu)票張數(shù)。Pi進(jìn)程的工作流程如下圖所示,用P操作和Ⅴ操作實(shí)現(xiàn)進(jìn)程間的同步與互斥。初始化時(shí)系統(tǒng)應(yīng)將信號(hào)量S賦值為(24)。圖中(a)、(b)和(c)處應(yīng)分別填入(25)。

    A.n-1
    B.0
    C.1
    D.2
    A.V(S)、P(S)和P(S)
    B.P(S)、P(S)和V(S)
    C.V(S)、V(S)和P(S)
    D.P(S)、V(S)和V(S)

    查看答案

    試題參考答案:C、D

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題5

    下圖是一個(gè)軟件項(xiàng)目的活動(dòng)圖,其中頂點(diǎn)表示項(xiàng)目里程碑,連接頂點(diǎn)的邊表示包含的活動(dòng),則一共有(7)條關(guān)鍵路徑,關(guān)鍵路徑長(zhǎng)度為(8) 。

    (7)
    A.2
    B.4
    C.3
    D.1
    (8)
    A.48
    B.55
    C.30
    D.46

    查看答案

    試題參考答案:B、B

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題6

    在程序運(yùn)行過(guò)程中,CPU 需要將指令從內(nèi)存中取出并加以分析和執(zhí)行。CPU 依據(jù)( )來(lái)區(qū)分在內(nèi)存中以二進(jìn)制編碼形式存放的指令和數(shù)據(jù)。
    A.指令周期的不同階段
    B.指令和數(shù)據(jù)的尋址方式
    C.指令操作碼的譯碼結(jié)果
    D.指令和數(shù)據(jù)所在的存儲(chǔ)單元

    查看答案

    試題參考答案:A

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題7

    (  )開(kāi)發(fā)過(guò)程模型最不適用開(kāi)發(fā)初期對(duì)軟件需求缺乏準(zhǔn)確全面認(rèn)識(shí)的情況。
     A.瀑布
     B.演化
     C.螺旋
     D.增量

    查看答案

    試題參考答案:A

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題8

    開(kāi)發(fā)專家系統(tǒng)時(shí),通過(guò)描述事實(shí)和規(guī)則由模式匹配得出結(jié)論,這種情況下適用的開(kāi)發(fā)語(yǔ)言是( )。
    A、面向?qū)ο笳Z(yǔ)言
    B、函數(shù)式語(yǔ)言
    C、過(guò)程式語(yǔ)言
    D、邏輯式語(yǔ)言

    查看答案

    試題參考答案:D

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題9

    某類圖如圖所示,下列選項(xiàng)錯(cuò)誤的是(  )。

    A.一個(gè)A1的對(duì)象可能與一個(gè)A2的對(duì)象關(guān)聯(lián)
    B.一個(gè)A的非直接對(duì)象可能與一個(gè)A1 的對(duì)象關(guān)聯(lián)
    C.類B1的對(duì)象可能通過(guò)A2與C1的對(duì)象關(guān)聯(lián)
    D.有可能A的直接對(duì)象與B1的對(duì)象關(guān)聯(lián)

    查看答案

    試題參考答案:D

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

  • 試題10

    Low-code and no code software development solutions have emerged as viable and convenient alternatives to the traditional development process.
    Low-code is a rapid application development (RAD) approach that enables automated code generation through(71) building blocks like drag-and-drop and pull-down menu interfaces.This (72) allows low-code users to focus on the diferentiator rather than the common denominator of programming. Low-code is a balanced middle ground between manual coding and no-code as its users can still add code over auto-generated code.While in low-code there is some hand holding done by developers in the form of scripting or manual coding, no-code has a completely (73) approach, with 100% dependence on visual tools.
    A low-code application platform (LCAP)——also called a low-code development platform (LCDP)——contains an integrated development environment (IDE) with (74) features like APIs, code templates, reusable plug-in modules and graphical connectors to automate a significant percentage of the application development process.LCAPs are typically available as cloud-based Platform-as-a-Service (PaaS) solutions.
    A low-code platform works on the principle or lowering complexity by using visual to and techniques like  process modeling. where users employ visual tools to define workflobusiness rules, user interfaces and the like.Behind the scenes, the complete workflovautomatically converted into code. LCAPs are used predominantly by professional developeautomate the generic aspects of coding to redirect effort on the last mile of (75).
    (71)
    A.visual
    B.component-based
    C.object-oriented
    D.structural
    (72)
    A.block
    B.a(chǎn)utomation
    C.function
    D.method
    (73)
    A.modern
    B.hands-off
    C.generic
    D.labor-free
    (74)
    A.reusable
    B.built-in
    C.existed
    D.well-known
    (75)
    A.delivery
    B.a(chǎn)utomation
    C.development
    D.success

    查看答案

    試題參考答案:A、B、B、B、C

    試題解析與討論:m.yifanwine.com/exam/ExamDay.aspx?t1=4&day=2025/11/9

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